Last Problem:
You see three faces on each of three dice for a total of nine faces. If the sum of the dots on each die is different and you see a total of forty dots altogether, then which faces (showing which numbers) must be visible on each of the three dice?
Answer:
The largest sum you can conceivable see on any dice is 15; that is, the sum of 4,5,6. Therefore, the only possible combinations of three different numbers that total 40 are 15+14+11 and 15+13+12. But, a sum of 13 is impossible to see on three faces of a dice. (If you do not believe me, try it out for yourself). This leaves the only answer as 15, 14 and 11.
This means that one dice will show 6, 5 and 4 dots on the three sides (which equals 15); one dice will show 6, 5 and 3 dots (which equals 14); And, one dice will show 6, 3 and 2 dots (which equals 11).
Today’s Problem:
A girl throws four balls randomly into any or all of four boxes. She always succeeds in getting the ball into one of the four boxes. But of course, it is possible that some boxes may have more than one ball. What are the chances that after she throws four balls, each box will each contain a single ball?